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8.3x=5x^2
We move all terms to the left:
8.3x-(5x^2)=0
determiningTheFunctionDomain -5x^2+8.3x=0
a = -5; b = 8.3; c = 0;
Δ = b2-4ac
Δ = 8.32-4·(-5)·0
Δ = 68.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8.3)-\sqrt{68.89}}{2*-5}=\frac{-8.3-\sqrt{68.89}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8.3)+\sqrt{68.89}}{2*-5}=\frac{-8.3+\sqrt{68.89}}{-10} $
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